How To Find Cutting Length Of Bar

How to summate Cutting length of Stirrups in Axle and column

Dec 23, 2018 Construction

To cater the stresses and loads in RCC, Bars are bent to unlike shapes in the bar angle schedule.

Different shapes of bars take different cutting length. In this mail service, we are going to explicate you about "How to calculate or observe the cutting length of Stirrups for different shapes".

Think,

The transverse reinforcement provided in Column is called Ties and the transverse reinforcement provided in Axle is called Stirrups. But on-site, we normally call both transverse reinforcements as Stirrups.

The prime reason for providing the stirrups in the beam is for shear requirements and to keep the longitudinal bars in position. If yous wanted to know more about the why stirrups & ties provided in the beam and column you tin refer here

Deducting the concrete cover is most important in Bar bending, if yous dont know how to deduct the concrete cover then refer this postal service

Concrete Cover deductions in Beams, Columns, Slab, Footings

Steps involved in finding the cutting length of stirrups:-

Wait at the size of column or beam from drawings
Adopt Dia of the bar (more often than not 8mm Dia is used for stirrups)
Deduct the concrete encompass or articulate cover
Find the total outer length of stirrup afterward deducting concrete embrace.
Add the length of the hook to the length of the stirrup
Deduct the length of bends
Use below formula to find the total cutting length of stirrups

Formula:

Cut Length of Stirrups = Perimeter of Shape + Total hook length – Total Bend Length

Important Basic formulas:

Perimeter of Rectangle = ii ( length + latitude)

Perimeter of Square = 4 x side length

Perimeter of circle or Circumference of Circle = 2πr = πd (r= radius, d= Bore of Circumvolve)

Typical Diagram of Stirrup:-

Refer the below image of the typical diagram of stirrup for clear understanding nigh x & y length, bends, hooks and concrete cover.

In the above paradigm, at that place are 5 bends at four corners, two hooks and concrete embrace around the stirrup.
x = length of the stirrup in the x-direction after deducting concrete encompass &
y = length of the stirrup in the y-management later on deducting concrete cover.

Important standards used in Bends & Hooks:

The beneath standards are well-nigh of import in computing the hook length and bend lengths at corners while finding cutting length of stirrups.

1 Hook length = 9d or 75mm
45° Bend length = 1d
xc° Curve length = 2d
135° Bend length = 3d

Remember, d = Diameter of Bar

Cut length for Rectangular Stirrups:-

Rectangular column or rectangular beam is the most commonly used shape of the column in whatsoever structure. In this shape of beam or cavalcade, a rectangular stirrup is usually adopted.

Considering the below Rectangular column size 230mm x 450mm for calculation purpose
Adopting Dia of Bar used for stirrups is 8mm
Deducting the concrete cover 20mm from all sides
x = 230 – 20-20 = 190mm
y = 450-20-twenty = 410mm
Total Length of the hooks:
From fig, At that place are two hooks which ways 9d+9d = 18d
Total Length of Bends:
From above fig, There are 3 bends which are bent at an angle of xc⁰ and two bends are aptitude at an angle of 135⁰
Total bend length = 3 x 90⁰ Bend length + 2 ten 135⁰ Bend length = 3 x 2d + ii x 3d = 12d = 12 x eight = 96mm

Total Cutting length of Rectangular Stirrup = Perimeter of Rectangle + Full Hook length – Total Curve Length

= two (10+y) +18d – 12d = ii(190 + 410) + 18 ten 8 – 12 x 8 = 1248mm = 1.248m

Cutting length for Foursquare Stirrups:-

Considered the column size equally 450mm x 450mm
Adopting Dia of Bar used for stirrups is 8mm
Deducting the concrete comprehend 25mm from all sides (in foursquare all sides are equal)
x = 450- xx-20 = 410mm
y = 450-twenty-20 = 410mm, Hence x = y (in square all sides are equal)
Total Length of the claw:
In that location are two hooks which hateful 9d+9d = 18d
Total length of Bends:
There are 3 bends which are aptitude at an angle of xc⁰ and one is aptitude at an angle of 135⁰.
Total curve length = 3 x xc⁰ Bend length + 2 x 135⁰ Curve length = 3 x 2d + 2 x 3d = 12d = 12 ten viii = 96mm

Full Cutting length of Square Stirrup = Perimeter of Square + Full Hook length – Total Bend Length

= 4 x 410 +18d – 12d = 1648mm = ane.64m

Cutting Length for Circular Stirrup:

Considered the column dia as D = 1000mm
Adopting Dia of Bar used for stirrups is d =8mm
Deducting the physical cover from diameter of column
D = 1000-25-25 = 950mm
Circumference length of Ring = πD = 950 ten iii.fourteen = 2983mm
Total Length of the claw:
There are ii hooks which means 9d+9d= 18d
Total Length of Bends:
There are two bends which are bent at an angle of 135⁰
Total bend length = 2 x 135⁰ Bend length = ii x 3d = 6d= 6 x eight = 48mm

Total Cutting length of Circular Stirrup or Ring = Circumference of Circle + Total Claw length – Total Bend Length
= 2983 +18d – 6d =3079mm =3.07m

Cutting Length for Triangular Stirrups:

Considered the Cavalcade size 400mm x 450mm
Adopting Dia of Bar used for stirrups is d = 8mm
Deducting the concrete cover 25mm from all sides
ten = 400-twenty-twenty = 360mm
y = 450-20-20 = 410mm
From Pythagorean theorem,
Hypotenuse²=(Contrary)^two + (Adjacent)²

look at 2nd triangle in above prototype
Hⁱⁱ=(ten/2)² + y²
H²=180² + 410ⁱⁱ => = √(447)² = 447mm
The total length of stirrup till at present = 2 x H + 360 = 2 x 447 + 360 = 1254mm
Full Length of the hooks:
In that location are two hooks which ways 9d+9d= 18d
Full length of Bends:
There are iv bends which are bent at an angle of 135⁰
Full curve length =4 10 135⁰ Bend length= 4 x 3d = 12d= 12 ten 8 = 96mm

Full Cut length of Triangular Stirrup = Perimeter of Triangle + Total Hook length – Total Curve Length

= 1254+18d – 12d = 1302mm = 1.3m

Cutting Length for Diamond Stirrups:

Considered the Column size 400mm x 400mm
Adopting Dia of Bar used for stirrups is d = 8mm
Deducting the concrete cover 25mm from all sides
x = 400-20-20 = 360mm
y = 400-20-20 =360mm

From Pythagorean theorem,
Hypotenuse²=(Opposite)^two + (Side by side)²
Hⁱⁱ=(x/2)² +( y/two)²
H^two=180² + 180ⁱⁱ => = √(254)² = 254mm
The total length of stirrup = 4 x H =iv x 254 = 1016mm
Total Length of the claw:
In that location are two hooks which means 9d+9d= 18d
Total length of Bends:
At that place are three bends which are bent at an bending of xc⁰ + 2 bends which are bent at an angle of 135⁰
Total curve length = 3 x ninety⁰ Bend length + 2 10 135⁰ Bend length= 3 x 2d + 2 x 3d = 12d = 12 x 8 = 96mm

Total Cut length of Diamond Stirrup = Perimeter of Diamond shape + Total Hook length – Total Curve Length
= 1016+144-96 = 1064mm = ane.064mm

Read more about how to Estimate the Quantities of Steel (Bar Bending Schedule) for unlike members of a structure:

I hope at present you can easily discover the cut length for unlike types of stirrups.

If you have whatsoever doubts yous can post them on our Forum

About The Writer

admin

Founder & Admin of civilread.com, I am a ceremonious engineer working in Ultratech Cement Ltd. With a good subject knowledge in civil engg i have started this blog to share valuable data to fellow civil engineers. Y'all can also follow me on fb and twitter by clicking below